1890 Belgian General Election
10 June 1890 · The censitaire kingdom · 69 seats, 70 for a majority
Under the alternating system, elections were held in only four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders. Thus, only 69 seats out of the 138 were up for election.
A censitaire election: only taxpaying men — around one to two per cent of the population — could vote. Recorded here as history, not a mass democratic election.
Prime Minister before
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Prime Minister (continued)
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Largest force
Liberal Party
40 of 69 seats
Turnout
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The result
| Share of the Chamber of Representatives | |||||||
|---|---|---|---|---|---|---|---|
| Liberal Party | — | 40 | +44 | 20,829 | 54.5% | — | |
| Catholic Party | Auguste Beernaert | 29 | +94 | 17,253 | 45.1% | — |